Chemistry: investigate the world of substances Lesson 41 of 49
How can we count particles too numerous to count one by one?
Introduce the mole and the Avogadro constant, always naming the entities being counted.
Support map
Model diagram
Use only paper, a calculator and supplied data. Do not carry out reactions, generate gases, heat substances or mix household chemicals.
Situation and question
A report says “we used 1 mole”. That is incomplete: 1 mole of water molecules and 1 mole of hydrogen atoms describe different sets. How can a short quantity describe an enormous count? Work with numbers and paper cards, without samples or balances.
New terms, fully explained
Amount of substance n measures the number of specified entities. Its unit, the mole (mol), contains exactly 6.02214076 × 10²³ specified entities. The Avogadro constant Nₐ is exactly 6.02214076 × 10²³ mol⁻¹. N is the dimensionless entity count. The relation is N = nNₐ. Approximate calculations here use Nₐ ≈ 6.02 × 10²³ mol⁻¹.
Predict first
Compare 0.5 mol of H₂O molecules with 0.5 mol of CO₂ molecules: which has more molecules? Then compare the total atom counts. Explain why equal molecule counts need not mean equal masses or equal numbers of atoms of each element.
Investigate or analyse given data
Build a table: 1 mol of H₂O molecules contains 1 mol of molecules, 2 mol of H atoms and 1 mol of O atoms, or 3 mol of atoms in total. For NaCl, count formula units describing the crystal composition rather than separate NaCl molecules. When counting ions, name their species and charge.
| Entity / step | Given / calculation | Result |
|---|---|---|
| H₂O | 1 mol | 2 mol H + 1 mol O |
| H₂O | 0.5 mol | N ≈ 3.01 × 10²³ |
| CaCl₂ | 1 mol | 2 mol Cl⁻ |
Worked example
For 0.5 mol of H₂O molecules, N ≈ 0.5 × 6.02 × 10²³ = 3.01 × 10²³ molecules. There are twice as many H atoms, 6.02 × 10²³, and as many O atoms as molecules. These are estimates using a rounded constant; the definition of the mole remains exact.
A common mistake
Mistake: “a mole is a mass in grams”, or “water has as many H atoms as molecules”. The mole measures amount; the gram measures mass. The subscript 2 in H₂O multiplies the H atom count. The number 6.02 × 10²³ is not a particle mass.
Transfer to a new case
Transfer: a set contains 0.25 mol of O₂ molecules. Find the amount of O atoms and the approximate molecule count. Also find how many moles of Cl⁻ ions correspond to the composition of 1 mol of CaCl₂ formula units. No actual dissolution is needed.
Answer and recall
Check: 0.50 mol of O atoms; approximately 1.51 × 10²³ O₂ molecules; 2 mol of Cl⁻ ions in the CaCl₂ composition. Reconstruct “name the entity → find n → multiply by Nₐ → account for subscripts”. Check units and round only the final result.
Exercise
How many mol of H atoms are in 0.10 mol H₂O? How many mol of Cl⁻ correspond to 0.30 mol CaCl₂?
Answers
Show the answers
0.20 mol of H atoms; 0.60 mol of Cl⁻ ions. Always specify the entity.
When to revisit
Close the page and, after 10 minutes, reconstruct the map, define the terms in your own words and solve the new case. Repeat without hints after a day and a week. If an error persists, return to the worked example and write down the missing step.
Sources and limits
The salt case: how do we check a transformation without losing matter?
If you have found a mistake or a typo in this article, tell us about it
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