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Why is a strong acid not necessarily concentrated?
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Chemistry: investigate the world of substances Lesson 62 of 67

Why is a strong acid not necessarily concentrated?

Separate extent of ionisation from the amount of substance per litre.

Support map

Why is a strong acid not necessarily concentrated?

Model diagram

Ten acid units comprise nine HA and one A⁻, with one accompanying H₃O⁺. Supplied ionised fraction is one tenth and net charge zero; water is omitted.

Use paper, a calculator and supplied data only. Do not taste, smell, mix or heat chemicals; do not open household products or unknown containers. Neutral pH does not establish safety. Do not apply teaching neutralisation to skin, eyes, spills or unknown mixtures.

Situation and question

Two notebook entries use “strong acid” and “concentrated solution” as synonyms. One describes behaviour in water; the other describes solution composition. What evidence is needed for each claim? Recall lesson 56 on molar concentration. No tasting or mixing of samples is required.

New terms, fully explained

Acid strength concerns ionisation equilibrium in a specified solvent: a strong monoprotic acid is essentially completely ionised in our dilute aqueous model; a weak acid is partly ionised. Analytical concentration c₀ counts the acid introduced regardless of its present form. The ionised fraction α is the share of original acid units that have ionised.

Predict first

Predict whether a more concentrated weak acid could provide more H₃O⁺ than a very dilute strong acid. Names alone cannot decide. Compare c₀ and equilibrium information. For a weak acid, α is not a fixed fraction that remains identical at every dilution.

Investigate or analyse given data

A supplied monoprotic HA model contains ten acid units: one appears as A⁻ with H₃O⁺, while nine remain HA. Water is omitted; this is a schematic given state, not a measured micrograph. Find α. Separate cards give c₀=0.010 mol/L with α=0.10, and c₀=0.00010 mol/L with α≈1.

Object / step Given / calculation Conclusion
HA 9 HA + A⁻ + H₃O⁺ α = 1/10
c₀ = 0.010; α = 0.10 c₀ × α 0.0010 mol/L
c₀ = 0.00010; α ≈ 1 c₀ × α ≈ 0.00010 mol/L

Worked example

The picture has α=1/10=0.10. In the first numerical card, the acid contributes approximately 0.010×0.10=0.0010 mol/L hydronium; the second gives approximately 0.00010 mol/L. With water’s contribution negligible, the partly ionised example provides more hydronium. Each card supplies its own α.

A common mistake

Mistake: calling weak acids harmless or assuming strong acids must be concentrated. Hazards require composition, concentration and product documentation. Do not carry α=0.10 to a different solution without evidence. HA + H₂O ⇌ H₃O⁺ + A⁻ conserves atoms and charge at any applicable extent of ionisation.

Transfer to a new case

Transfer case: X contains a weak monoprotic acid with c₀=0.020 mol/L and supplied α=0.05. Y contains a strong acid with c₀=0.00020 mol/L. Find approximate hydronium concentrations and X/Y, assuming the dilute model applies and water contributes negligibly. What information is needed after diluting X?

Answer and recall

Check: X gives 0.0010 mol/L and Y 0.00020; the ratio is five. Diluted X needs a new equilibrium state or an acid constant and calculation; its old α cannot simply be retained. Explain why strength, concentration and hazard are three distinct descriptions.

Exercise

For c₀=0.030 mol/L and supplied α=0.020, find HA’s hydronium contribution. Does α survive every dilution unchanged?

Answers

Show the answers

0.00060 mol/L under the stated assumptions; no, a new equilibrium is needed.

When to revisit

Close the page and, after 10 minutes, reconstruct the map, define the terms in your own words and solve the new case. Repeat without hints after a day and a week. If an error persists, return to the worked example and write down the missing step.

Sources and limits

Why does one pH unit represent a tenfold difference?

What changes in neutralisation, and which ions remain?

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Check your solution

Solve the problem on paper first. Enter your reasoning, calculations, units, and explanation here. The model will review the solution, identify the first incorrect or unsupported step, and give a small hint without revealing the finished answer.

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